设计c++程序计算字符串s中包含字母数量大于n的单词个数

var
a,i,max,min:longint;
begin
max:=-maxlongint;
min:=maxlongint;
for i:=1 to 10 do
begin
read(a);
if a<min then min:=a;
if a>max then max:=a;
end;
writeln(min,' ',max);
end.

---

#include<fstream.h>
#define N 50

int alpha(char c){//判断一个字符是否为字母
if(c>='a'&&c<='z')return 1;
if(c>='A'&&c<='Z')return 1;
else return 0;
}

void main(){
int i,n,k,num=0;
char s[N];
cout<<"请输入字符串s"<<endl;
cin.getline(s,N);//连空格一起接收N个字符，当作字符串s
cout<<"n=";
cin>>n;
for(i=0;i<N&&s[i]!='{answer}';i++){
if(alpha(s[i])){
for(k=0;alpha(s[i]);i++,k++);//找到字母开头的串则查看这个字母串的长度k
if(k>n)num++;//串长度大于等于n，计数器+1
}
}
cout<<"字母数量大于n的单词个数为"<<num<<"个"<<endl;
}